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已采纳

int yu,shu,ying;
cin>>yu>>shu>>ying;
if(yu>=110&&shu>=130&&ying>=85)
cout<<"Yes";
if(yu<110||shu<130||ying<85)
cout<<"No";
语文满分120分,110分及以上优秀;数学满分150分,130分及以上算优秀;英语满分100分,85分以上算优秀。(if(yu>=110&&shu>=130&&ying>=85) cout<<"Yes";)
然后算if分都低于优秀分,输出No
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核心代码
cin>>c>>m>>e;
if (c>=110 and m>=130 and e>85) cout<<"Yes"<<endl;
else cout<<"No"<<endl;
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