0
0
for(int i=1;i<=8;i++)
{
e+=t;
t=(float)t/2;
e+=t*2;
// printf("e=%.4f\n",e);
// printf("t=%.4f\n",t);
}
e=(int)(e*10000+0.5)/10000.0;
t=(int)(t*10000+0.5)/10000.0;
0
double d=0,H;
定义 h;
输入>>h;
d=h;
H=h;
循环(int i=2;i<=8;i++){
H=H/2;
d+=2*H;
}
printf("%.4f\n",(int)(d*10000+0.5)/10000.0);
printf("%.4f\n",(int)(H/2*10000+0.5)/10000.0);
0
double d=0,H;
int h;
cin>>h;
d=h;
H=h;
for(int i=2;i<=8;i++){
H=H/2;
d+=2*H;
}
printf输出("%.4f\n",(int)(d*10000+0.5)/10000.0);
printf输出("%.4f",(int)(H/2*10000+0.5)/10000.0);
0
0
