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已采纳
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if (!(a>120)&&!(a<110)&&!(b>150)&&!(b<130)&&!(c>100)&&!(c<85))
cout<<"Yes"<<endl;
然后else 输出No
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这样做:
if (!(a>120)&&!(a<110)&&!(b>150)&&!(b<130)&&!(c>100)&&!(c<85))
cout<<"Yes"<<endl;
else
cout<<"No"<<endl;
变量样定义成:
double
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readln(a,b,c);
if (a>=110) and (b>=130) and (c>=85) then
writeln('Yes')
else
writeln('No');
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