0
已采纳
double h,sum=0,i=1;
cin>>h;
do
{
i++;
sum+=h;
h=h/2;
sum+=h;
}while(i<=8);
sum-=h;
printf("%.4f\n%.4f",int(sum*10000+0.5)/10000.0,int(h*10000+0.5)/10000.0);
0
double s=0.0,h;
cin>>h;
s=s-h;
int i=1;
while(i<=8)
{
s=s+2*h;
h=h/2;
i++;
}
printf("%.4lf",int(s*10000+0.5)/10000.0);
cout<<endl;
printf("%.4lf",int(h*10000+0.5)/10000.0);
0
double s,a;
cin>>a;
s-=a;
for(int i=1;i<=8;i++)
{
s=s+2*a;
a=a/2;
}
printf("%.4f\n",int(s*10000+0.5)/10000.0);
printf("%.4f",int(a*10000+0.5)/10000.0);
0
