问题标题: 1672

Question

0

已解决

杨子逸

新手天翼

#include<iostream>
#include<cstdio>
#include<cmath>
#include<cstring>
using namespace std;
int main()
{
    int a,b;
    cin>>a>>b;
    if(a%2==0)
    {
        if(b%2==0)
        cout<<"Yes";
        else
        cout<<"No";
    }
    else if(a%2!=0)
    {
        if(b%2==0)
        cout<<"No";
        else
        cout<<"Yes";
    }
    return 0;
}

//90分

杨子逸在2018-01-18 12:20:38追加了内容

#include<iostream>
#include<cstdio>
#include<cmath>
#include<cstring>
using namespace std;
int main()
{
    int a,b;
    cin>>a>>b;
    if(a%2==0)
    {
        if(b%2==0)
        cout<<"Yes";
        else
        cout<<"No";
    }
    else if(a%2!=0)
    {
        if(b%2==0)
        cout<<"No";
        else
        cout<<"Yes";
    }
    return 0;
}

//90

#include<iostream>
#include<cstdio>
#include<cmath>
#include<cstring>
using namespace std;
int main()
{
int m,n;
cin>>m>>n;
if((m==7||n%2==m%2)?(cout<<"Yes"):(cout<<"No"));
return 0;
}

错的，80

Answer 1

已采纳

张睿杰

初级天翼

((m==7||n%2==m%2)?(cout<<"Yes"):(cout<<"No"));

搞定

Answer 2

郑怡翔

初级天翼

前面先定义，输入后判断b是不是==7，如果是，cout<<"Yes";return 0;

核心：

if(a%2==0)
    {
        if(b==1 || b==3 || b==5)
        {
            cout<<"No";
        }
        else if(b==2 || b==4 || b==6)
        {
            cout<<"Yes";
        }
 }

然后判断a是不是奇数如果是，b是奇数的话输出"Yes",否则输出"No";

Answer 3

蔡辰夕

新手启示者

231321231

Answer 4

谢其桦

资深守护

((m==7||n%2==m%2)?(cout<<"Yes"):(cout<<"No"));

Answer 5

欧阳语聪

资深守护

    if(b==7){
            cout<<"Yes";
}
    else if(a%2==b%2){
    cout<<"Yes";
}
    else{
        cout<<"No";
    }

Answer 6

褚福磊

新手光能

((m==7||n%2==m%2)?(cout<<"Yes"):(cout<<"No"));

完成

Answer 7

何楷睿

高级守护

((m==7||n%2==m%2)?(cout<<"Yes"):(cout<<"No"));

Answer 8

栾峻岩

初级天翼

先判断a%2==0,如果是，在判断n=1或3或5或7.如果是，输出：“No”,若不是，输出：“Yes”;

如果a%2==1，再判断n%2,如果是1，输出：“Yes”,不是，输出：“No”.

问题标题: 1672

8 个回答: